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A particle Q of mass m falls under gravity in a medium whose resistance to motion is of magnitude mkv2 , where v is the speed of Q and k is a positive constant. Given that the maximum speed of Q is U, show that U=Square root of g/k. g is the acceleration due to gravity.Ã‚ÂGiven that Q is projected vertically upwards with speed V(>U), show that the speed of Q is equal to U whenÃ‚ÂtheÃ‚Â height of Q above the point of projection is (U2/2g)ln[(1/2)(1+Ã‚Â V2/U2)]Find in terms of U, V and g, the time taken for the speed of Q to decrease from V to U.Ã‚ÂÃ‚Â
A particle Q of mass m falls under gravity in a medium whose resistance to motion is of magnitude mkv^{2} , where v is the speed of Q and k is a positive constant. Given that the maximum speed of Q is U, show that U=Square root of g/k. g is the acceleration due to gravity.Ã‚Â
Given that Q is projected vertically upwards with speed V(>U), show that the speed of Q is equal to U whenÃ‚ÂtheÃ‚Â height of Q above the point of projection is (U^{2}/2g)ln[(1/2)(1+Ã‚Â V^{2}/U^{2})]
Find in terms of U, V and g, the time taken for the speed of Q to decrease from V to U.Ã‚Â
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1 Approved Answer
Subhash P
3Ratings (16 Votes)
The equation of motion for particle be defined as,
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